(x^2+2x-8)=(x-6)

Solution for (x^2+2x-8)=(x-6) equation:

(x^2+2x-8)=(x-6)

We move all terms to the left:

(x^2+2x-8)-((x-6))=0

We get rid of parentheses

x^2+2x-((x-6))-8=0


We calculate terms in parentheses: -((x-6)), so:

(x-6)

We get rid of parentheses

x-6

Back to the equation:

-(x-6)


We get rid of parentheses

x^2+2x-x+6-8=0

We add all the numbers together, and all the variables

x^2+x-2=0

a = 1; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·1·(-2)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-3}{2*1}=\frac{-4}{2}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+3}{2*1}=\frac{2}{2}
=1
$